What is (3x^{a+1})(2x^a)(-x^{-2a}) ?

The solution to (3x^{a+1})(2x^a)(-x^{-2a}) is -6x

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simplify (3x^{a+1})(2x^a)(-x^{-2a})

simplify

(3 x^{a + 1}) (2 x^{a}) (- x^{- 2 a})

- 6 x

Solution steps

(3 x^{a + 1}) (2 x^{a}) (- x^{- 2 a})

Apply rule:

a (- b) = - ab

(3 x^{a + 1}) (2 x^{a}) (- x^{- 2 a}) = - 3 x^{a + 1} \cdot 2 x^{a} x^{- 2 a}

= - 3 x^{a + 1} \cdot 2 x^{a} x^{- 2 a}

Multiply the numbers:

- 3 \cdot 2 = - 6

= - 6 x^{a + 1} x^{a} x^{- 2 a}

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

x^{a + 1} x^{a} x^{- 2 a} = x^{a + 1 + a - 2 a}

= - 6 x^{a + 1 + a - 2 a}

a + 1 + a - 2 a = 1

= - 6 x^{1}

Apply exponent rule:

a^{1} = a

x^{1} = x

= - 6 x

\frac{7 x ^{2} - 25 x - 12}{7 x - 28}

12 x^{2} + 22 x + 8

\frac{6 y - 9 y}{9 x y}

- 3 x^{2} + 15 x + 108

25 x^{4} - 10 x^{2} y^{2} + y^{4} - 100

What is (3x^{a+1})(2x^a)(-x^{-2a}) ?
The solution to (3x^{a+1})(2x^a)(-x^{-2a}) is -6x