What are the solutions to the equation 2x^2+11x=6 ?

The solutions to the equation 2x^2+11x=6 are x= 1/2 ,x=-6

Find the zeros of 2x^2+11x=6

The zeros of 2x^2+11x=6 are x= 1/2 ,x=-6

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2 x^{2} + 11 x = 6

x = \frac{1}{2}, x = - 6

Decimal Notation

x = 0.5, x = - 6

Solution steps

2 x^{2} + 11 x = 6

Move

6

to the left side

2 x^{2} + 11 x - 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 11 \pm 1 1 ^{2} - 4 \cdot 2 ( - 6 )}{2 \cdot 2}

1 1^{2} - 4 \cdot 2 (- 6) = 13

x_{1, 2} = \frac{- 11 \pm 13}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 11 + 13}{2 \cdot 2}, x_{2} = \frac{- 11 - 13}{2 \cdot 2}

x = \frac{- 11 + 13}{2 \cdot 2} : \frac{1}{2}

x = \frac{- 11 - 13}{2 \cdot 2} : - 6

The solutions to the quadratic equation are:

x = \frac{1}{2}, x = - 6

(3 n + 1)^{2} + 6 (3 n + 1) - 7 = 0

- 7.4 = - 2.5 + x

(- 1)^{1}

\frac{\frac{y}{2} - \frac{1}{x}}{\frac{6 y}{x}}

- 5 x \geq 50

What are the solutions to the equation 2x^2+11x=6 ?
The solutions to the equation 2x^2+11x=6 are x= 1/2 ,x=-6
Find the zeros of 2x^2+11x=6
The zeros of 2x^2+11x=6 are x= 1/2 ,x=-6