What is (20(a^{-4}b^{-2}))/(8(a^{-2)b^4)^{-2}} ?

The solution to (20(a^{-4}b^{-2}))/(8(a^{-2)b^4)^{-2}} is (5b^6)/(2a^8)

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simplify (20(a^{-4}b^{-2}))/(8(a^{-2)b^4)^{-2}}

simplify

\frac{20 ( a ^{- 4} b ^{- 2} )}{8 ( a ^{- 2} b ^{4} ) ^{- 2}}

\frac{5 b ^{6}}{2 a ^{8}}

Solution steps

\frac{20 ( a ^{- 4} b ^{- 2} )}{8 ( a ^{- 2} b ^{4} ) ^{- 2}}

Factor the number:

20 = 4 \cdot 5

= \frac{4 \cdot 5 a ^{- 4} b ^{- 2}}{8 ( a ^{- 2} b ^{4} ) ^{- 2}}

Factor the number:

8 = 4 \cdot 2

= \frac{4 \cdot 5 a ^{- 4} b ^{- 2}}{4 \cdot 2 ( a ^{- 2} b ^{4} ) ^{- 2}}

Cancel the common factor:

4

= \frac{5 a ^{- 4} b ^{- 2}}{2 ( a ^{- 2} b ^{4} ) ^{- 2}}

Simplify

(a^{- 2} b^{4})^{- 2} : a^{4} \frac{1}{b ^{8}}

= \frac{5 a ^{- 4} b ^{- 2}}{2 a ^{4} \frac{1}{b ^{8}}}

Simplify

\frac{a ^{- 4}}{a ^{4}} : \frac{1}{a ^{8}}

= \frac{5 b ^{- 2}}{2 a ^{8} \frac{1}{b ^{8}}}

Simplify

\frac{5 b ^{- 2}}{2 a ^{8} \frac{1}{b ^{8}}} : \frac{5 b ^{6}}{2 a ^{8}}

= \frac{5 b ^{6}}{2 a ^{8}}

63 a^{13} - 3 700 a^{21} + 48 343 a^{33}

2 sin (x) + 2 cos (x)

8 \frac{1}{4} - 5 \frac{2}{3}

\frac{2 ^{3} \cdot 3 ^{4} \cdot 3 \cdot 4 ^{2} \cdot 2 ^{5} \cdot 4 ^{3}}{3 ^{4} \cdot 4 ^{3} \cdot 2 ^{5}}

\frac{1 + i}{1 + i}

What is (20(a^{-4}b^{-2}))/(8(a^{-2)b^4)^{-2}} ?
The solution to (20(a^{-4}b^{-2}))/(8(a^{-2)b^4)^{-2}} is (5b^6)/(2a^8)