What is (x^3-1)/(x^2-1)-(x+1) ?

The solution to (x^3-1)/(x^2-1)-(x+1) is (x^2+x+1)/(x+1)-x-1

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simplify (x^3-1)/(x^2-1)-(x+1)

simplify

\frac{x ^{3} - 1}{x ^{2} - 1} - (x + 1)

\frac{x ^{2} + x + 1}{x + 1} - x - 1

Solution steps

\frac{x ^{3} - 1}{x ^{2} - 1} - (x + 1)

Apply the distributive law:

- (a + b) = - a - b

- (x + 1) = - x - 1

= \frac{x ^{3} - 1}{x ^{2} - 1} - x - 1

Simplify

\frac{x ^{3} - 1}{x ^{2} - 1} : \frac{x ^{2} + x + 1}{x + 1}

= \frac{x ^{2} + x + 1}{x + 1} - x - 1

2 x - 6 y - 2 x - 3 y - 5 y

lo g_{3} (\frac{a ^{5} b}{c ^{2}})

\frac{70}{200}

ln (\frac{3}{2})

\frac{5}{4 ( x - 3 )} + \frac{11}{6 x ( x + 5 )}

What is (x^3-1)/(x^2-1)-(x+1) ?
The solution to (x^3-1)/(x^2-1)-(x+1) is (x^2+x+1)/(x+1)-x-1