What are the solutions to the equation 0=2x^2+5x-3 ?

The solutions to the equation 0=2x^2+5x-3 are x= 1/2 ,x=-3

Find the zeros of 0=2x^2+5x-3

The zeros of 0=2x^2+5x-3 are x= 1/2 ,x=-3

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0 = 2 x^{2} + 5 x - 3

x = \frac{1}{2}, x = - 3

Decimal

x = 0.5, x = - 3

Solution steps

0 = 2 x^{2} + 5 x - 3

Switch sides

2 x^{2} + 5 x - 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 2 ( - 3 )}{2 \cdot 2}

5^{2} - 4 \cdot 2 (- 3) = 7

x_{1, 2} = \frac{- 5 \pm 7}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 5 + 7}{2 \cdot 2}, x_{2} = \frac{- 5 - 7}{2 \cdot 2}

x = \frac{- 5 + 7}{2 \cdot 2} : \frac{1}{2}

x = \frac{- 5 - 7}{2 \cdot 2} : - 3

The solutions to the quadratic equation are:

x = \frac{1}{2}, x = - 3

9 - \frac{9 x}{7} = 12

\frac{2}{3} x + 7 + \frac{3}{4} x + 5 = 90

- 13 y = 5 y^{2} - 6

x^{4} + x^{2} - 2

8 (\frac{1}{8})

What are the solutions to the equation 0=2x^2+5x-3 ?
The solutions to the equation 0=2x^2+5x-3 are x= 1/2 ,x=-3
Find the zeros of 0=2x^2+5x-3
The zeros of 0=2x^2+5x-3 are x= 1/2 ,x=-3