What is (12-9n^2+5n^3)-(-11n^3-4n^2+6n) ?

The solution to (12-9n^2+5n^3)-(-11n^3-4n^2+6n) is 16n^3-5n^2-6n+12

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simplify (12-9n^2+5n^3)-(-11n^3-4n^2+6n)

simplify

(12 - 9 n^{2} + 5 n^{3}) - (- 11 n^{3} - 4 n^{2} + 6 n)

16 n^{3} - 5 n^{2} - 6 n + 12

Solution steps

(12 - 9 n^{2} + 5 n^{3}) - (- 11 n^{3} - 4 n^{2} + 6 n)

Apply rule:

(a) = a

(12 - 9 n^{2} + 5 n^{3}) = 12 - 9 n^{2} + 5 n^{3}

= 12 - 9 n^{2} + 5 n^{3} - (- 11 n^{3} - 4 n^{2} + 6 n)

Apply the distributive law:

- (- a - b) = a + b

- (- 11 n^{3} - 4 n^{2} + 6 n) = 11 n^{3} + 4 n^{2} - 6 n

= 12 - 9 n^{2} + 5 n^{3} + 11 n^{3} + 4 n^{2} - 6 n

Add similar elements:

5 n^{3} + 11 n^{3} = 16 n^{3}

= 12 - 9 n^{2} + 16 n^{3} + 4 n^{2} - 6 n

Group like terms

= 16 n^{3} - 9 n^{2} + 4 n^{2} - 6 n + 12

Add similar elements:

- 9 n^{2} + 4 n^{2} = - 5 n^{2}

= 16 n^{3} - 5 n^{2} - 6 n + 12

e^{x^{2} + 5 l n (x)}

10 \cdot 0! + 3! + 9 \cdot 1!

\frac{125 x ^{6}}{x}

2 sin (\frac{θ}{5}) cos (\frac{θ}{5})

1 6^{\frac{1}{2}} - 62 5^{\frac{1}{2}}

What is (12-9n^2+5n^3)-(-11n^3-4n^2+6n) ?
The solution to (12-9n^2+5n^3)-(-11n^3-4n^2+6n) is 16n^3-5n^2-6n+12