What is [1-(x+z)][1+(x+z)] ?

The solution to [1-(x+z)][1+(x+z)] is (1-x-z)(1+(x+z))

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simplify [1-(x+z)][1+(x+z)]

simplify

[1 - (x + z)] [1 + (x + z)]

(1 - x - z) (1 + (x + z))

Solution steps

(1 - (x + z)) (1 + (x + z))

Apply the distributive law:

- (a + b) = - a - b

- (x + z) = - x - z

= (1 - x - z) (1 + (x + z))

\frac{1}{cos ^{3} ( x )}

1 - (1)

\frac{- 1 ^{3}}{3}

2 \cdot 11

What is [1-(x+z)][1+(x+z)] ?
The solution to [1-(x+z)][1+(x+z)] is (1-x-z)(1+(x+z))