What is (3x^3-3x^2)/(x^3-x) ?

The solution to (3x^3-3x^2)/(x^3-x) is (3x)/(x+1)

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simplify (3x^3-3x^2)/(x^3-x)

simplify

\frac{3 x ^{3} - 3 x ^{2}}{x ^{3} - x}

\frac{3 x}{x + 1}

Solution steps

\frac{3 x ^{3} - 3 x ^{2}}{x ^{3} - x}

Factor

3 x^{3} - 3 x^{2} : 3 x^{2} (x - 1)

= \frac{3 x ^{2} ( x - 1 )}{x ^{3} - x}

Factor

x^{3} - x : x (x + 1) (x - 1)

= \frac{3 x ^{2} ( x - 1 )}{x ( x + 1 ) ( x - 1 )}

Cancel the common factor:

x - 1

= \frac{3 x ^{2}}{x ( x + 1 )}

Apply exponent rule:

a^{b + c} = a^{b} \cdot a^{c}

x^{2} = xx

= \frac{3 xx}{x ( x + 1 )}

Cancel the common factor:

x

= \frac{3 x}{x + 1}

4 x^{- 2} + 3 x^{- 5}

(- 7 - 8 i) - (2 + 8 i)

\frac{a ^{- 3} b ^{2}}{b ^{2} a ^{2}}

- 3 0^{2}

(1 - p)^{3}