What are the solutions to the equation x^2+32=0 ?

The solutions to the equation x^2+32=0 are x=4sqrt(2)i,x=-4sqrt(2)i

Find the zeros of x^2+32=0

The zeros of x^2+32=0 are x=4sqrt(2)i,x=-4sqrt(2)i

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x^{2} + 32 = 0

x = 42 i, x = - 42 i

Solution steps

x^{2} + 32 = 0

Move

32

to the right side

x^{2} = - 32

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - 32, x = - - 32

- 32 = 42 i

- - 32 = - 42 i

x = 42 i, x = - 42 i

\frac{( 2 mn ) ^{4}}{6 m ^{- 3} n ^{- 2}}

- y = \frac{6}{- 2}

4 x - 2 (x - 3) \geq 0

12 x^{3} - 69 x^{2} + 39 x + 30

(8 (- 393.5) + 10 (- 241.8)) - (2 (- 125.7))

What are the solutions to the equation x^2+32=0 ?
The solutions to the equation x^2+32=0 are x=4sqrt(2)i,x=-4sqrt(2)i
Find the zeros of x^2+32=0
The zeros of x^2+32=0 are x=4sqrt(2)i,x=-4sqrt(2)i