What is ((m^{-3}n^{-4})^8)/((m^2n^5)^{-7)} ?

The solution to ((m^{-3}n^{-4})^8)/((m^2n^5)^{-7)} is (n^3)/(m^{10)}

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simplify ((m^{-3}n^{-4})^8)/((m^2n^5)^{-7)}

simplify

\frac{( m ^{- 3} n ^{- 4} ) ^{8}}{( m ^{2} n ^{5} ) ^{- 7}}

\frac{n ^{3}}{m ^{10}}

Solution steps

\frac{( m ^{- 3} n ^{- 4} ) ^{8}}{( m ^{2} n ^{5} ) ^{- 7}}

Simplify

(m^{- 3} n^{- 4})^{8} : \frac{1}{m ^{24} n ^{32}}

= \frac{\frac{1}{m ^{24} n ^{32}}}{( m ^{2} n ^{5} ) ^{- 7}}

Apply the fraction rule:

\frac{\frac{a}{b}}{c} = \frac{a}{b \cdot c}

= \frac{1}{m ^{24} n ^{32} ( m ^{2} n ^{5} ) ^{- 7}}

Simplify

m^{24} n^{32} (m^{2} n^{5})^{- 7} : \frac{m ^{10}}{n ^{3}}

= \frac{1}{\frac{m ^{10}}{n ^{3}}}

Apply the fraction rule:

\frac{1}{\frac{b}{c}} = \frac{c}{b}

= \frac{n ^{3}}{m ^{10}}

\frac{y ^{2} - 16}{y + 4}

- 2 x \cdot x^{2}

(7 a - 1)^{2}

36 x^{2} - a^{6} b^{4}

What is ((m^{-3}n^{-4})^8)/((m^2n^5)^{-7)} ?
The solution to ((m^{-3}n^{-4})^8)/((m^2n^5)^{-7)} is (n^3)/(m^{10)}