What is 1/((s+1)(s+2))e^{-2s}+4 ?

The solution to 1/((s+1)(s+2))e^{-2s}+4 is (e^{-2s})/((s+1)(s+2))+4

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simplify 1/((s+1)(s+2))e^{-2s}+4

simplify

\frac{1}{( s + 1 ) ( s + 2 )} e^{- 2 s} + 4

\frac{e ^{- 2 s}}{( s + 1 ) ( s + 2 )} + 4

Solution steps

\frac{1}{( s + 1 ) ( s + 2 )} e^{- 2 s} + 4

\frac{1}{( s + 1 ) ( s + 2 )} e^{- 2 s} = \frac{e ^{- 2 s}}{( s + 1 ) ( s + 2 )}

= \frac{e ^{- 2 s}}{( s + 1 ) ( s + 2 )} + 4

lo g_{10} (2.4)

lo g_{10} (256)

1 \cdot 100

\frac{100 !}{2 ! ( 100 - 2 ) !}

6 \cdot 1 0^{4}

What is 1/((s+1)(s+2))e^{-2s}+4 ?
The solution to 1/((s+1)(s+2))e^{-2s}+4 is (e^{-2s})/((s+1)(s+2))+4