What is the answer to (x-3)^2+(x+1)^2=(x-2)^2+(x+3)^2 ?

The answer to (x-3)^2+(x+1)^2=(x-2)^2+(x+3)^2 is x=-1/2

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(x-3)^2+(x+1)^2=(x-2)^2+(x+3)^2

(x - 3)^{2} + (x + 1)^{2} = (x - 2)^{2} + (x + 3)^{2}

x = - \frac{1}{2}

Decimal Notation

x = - 0.5

Solution steps

(x - 3)^{2} + (x + 1)^{2} = (x - 2)^{2} + (x + 3)^{2}

Expand

(x - 3)^{2} + (x + 1)^{2} : 2 x^{2} - 4 x + 10

Expand

(x - 2)^{2} + (x + 3)^{2} : 2 x^{2} + 2 x + 13

2 x^{2} - 4 x + 10 = 2 x^{2} + 2 x + 13

Move

10

to the right side

2 x^{2} - 4 x = 2 x^{2} + 2 x + 3

Subtract

2 x^{2} + 2 x

from both sides

2 x^{2} - 4 x - (2 x^{2} + 2 x) = 2 x^{2} + 2 x + 3 - (2 x^{2} + 2 x)

Simplify

- 6 x = 3

Divide both sides by

- 6

x = - \frac{1}{2}

2 (h - 2) \leq - 2 (1 - h)

\frac{21}{3}

\frac{5}{7} \cdot 6

5^{\frac{1}{2}} + 2^{6}

x^{2} - 2 x - 15 > 0

What is the answer to (x-3)^2+(x+1)^2=(x-2)^2+(x+3)^2 ?
The answer to (x-3)^2+(x+1)^2=(x-2)^2+(x+3)^2 is x=-1/2
Solve for x: (x-3)^2+(x+1)^2=(x-2)^2+(x+3)^2
The solution is x=-1/2