What is (x^2+2x-3)/(x^2-1) ?

The solution to (x^2+2x-3)/(x^2-1) is (x+3)/(x+1)

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simplify (x^2+2x-3)/(x^2-1)

simplify

\frac{x ^{2} + 2 x - 3}{x ^{2} - 1}

\frac{x + 3}{x + 1}

Solution steps

\frac{x ^{2} + 2 x - 3}{x ^{2} - 1}

Factor

x^{2} + 2 x - 3 : (x - 1) (x + 3)

= \frac{( x - 1 ) ( x + 3 )}{x ^{2} - 1}

Factor

x^{2} - 1 : (x + 1) (x - 1)

= \frac{( x - 1 ) ( x + 3 )}{( x + 1 ) ( x - 1 )}

Cancel the common factor:

x - 1

= \frac{x + 3}{x + 1}

(- 1)^{\frac{3}{5}}

n^{4} - 9 n^{2} + 4 n^{3} - 36 n - 12 n^{2} + 108

\frac{2 x}{5 x}

27 \frac{- 2}{3}

\frac{2}{3} \div \frac{5}{4}