What is factor x^3-5x^2+3x+6 ?

The solution to factor x^3-5x^2+3x+6 is (x-2)(x^2-3x-3)

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factor x^3-5x^2+3x+6

factor

x^{3} - 5 x^{2} + 3 x + 6

(x - 2) (x^{2} - 3 x - 3)

Solution steps

x^{3} - 5 x^{2} + 3 x + 6

Use the rational root theorem

= (x - 2) \frac{x ^{3} - 5 x ^{2} + 3 x + 6}{x - 2}

\frac{x ^{3} - 5 x ^{2} + 3 x + 6}{x - 2} = x^{2} - 3 x - 3

= (x - 2) (x^{2} - 3 x - 3)

\frac{cos ^{2} ( x ) - sin ^{2} ( x )}{cos ^{2} ( x ) + sin ^{2} ( x )}

2 (3 - i) (- 2 + 4 i)

(x^{2} y - 3 y^{2} + 5 x y^{2}) - (- x^{2} y + 3 x y^{2} - 3 y^{2})

ln (1.7)

3 \cdot + 1

What is factor x^3-5x^2+3x+6 ?
The solution to factor x^3-5x^2+3x+6 is (x-2)(x^2-3x-3)