What is (\frac{2x-8)/(x+1)}{(3x^2-12x)/(x^2-1)} ?

The solution to (\frac{2x-8)/(x+1)}{(3x^2-12x)/(x^2-1)} is (2(x-1))/(3x)

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simplify (\frac{2x-8)/(x+1)}{(3x^2-12x)/(x^2-1)}

simplify

\frac{\frac{2 x - 8}{x + 1}}{\frac{3 x ^{2} - 12 x}{x ^{2} - 1}}

\frac{2 ( x - 1 )}{3 x}

Solution steps

\frac{\frac{2 x - 8}{x + 1}}{\frac{3 x ^{2} - 12 x}{x ^{2} - 1}}

Apply the fraction rule:

\frac{\frac{a}{b}}{\frac{c}{d}} = \frac{a \cdot d}{b \cdot c}

= \frac{( 2 x - 8 ) ( x ^{2} - 1 )}{( x + 1 ) ( 3 x ^{2} - 12 x )}

Cancel

\frac{( 2 x - 8 ) ( x ^{2} - 1 )}{( x + 1 ) ( 3 x ^{2} - 12 x )} : \frac{2 ( x - 1 )}{3 x}

= \frac{2 ( x - 1 )}{3 x}

2 (x + 5)^{2}

\frac{2 + \frac{2}{3}}{2 - \frac{1}{2}}

2 \frac{3}{4} \cdot \frac{4}{5}

x^{\frac{3}{2}} \cdot \frac{1}{x}

What is (\frac{2x-8)/(x+1)}{(3x^2-12x)/(x^2-1)} ?
The solution to (\frac{2x-8)/(x+1)}{(3x^2-12x)/(x^2-1)} is (2(x-1))/(3x)