What are the solutions to the equation (x^2+3)=4 ?

The solutions to the equation (x^2+3)=4 are x=1,x=-1

Find the zeros of (x^2+3)=4

The zeros of (x^2+3)=4 are x=1,x=-1

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(x^{2} + 3) = 4

x = 1, x = - 1

Solution steps

(x^{2} + 3) = 4

x^{2} + 3 = 4

Move

3

to the right side

x^{2} = 1

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 1, x = - 1

1 = 1

- 1 = - 1

x = 1, x = - 1

3 (\frac{x}{2} - 9) \leq - x - 18

(\frac{5}{3})^{- 3}

14 x^{2} + 5 x z - z^{2}

5 m^{2} + 13 m - 6

(2 x - 1)^{2} = 81

What are the solutions to the equation (x^2+3)=4 ?
The solutions to the equation (x^2+3)=4 are x=1,x=-1
Find the zeros of (x^2+3)=4
The zeros of (x^2+3)=4 are x=1,x=-1