What is (-7x^{-3}y)^2*2x^{-4}y^{-2} ?

The solution to (-7x^{-3}y)^2*2x^{-4}y^{-2} is (98)/(x^{10)}

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simplify (-7x^{-3}y)^2*2x^{-4}y^{-2}

simplify

(- 7 x^{- 3} y)^{2} \cdot 2 x^{- 4} y^{- 2}

\frac{98}{x ^{10}}

Solution steps

(- 7 x^{- 3} y)^{2} \cdot 2 x^{- 4} y^{- 2}

Simplify

(- 7 x^{- 3} y)^{2} : \frac{49 y ^{2}}{x ^{6}}

= \frac{49 y ^{2}}{x ^{6}} \cdot 2 x^{- 4} y^{- 2}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

x^{- 4} = \frac{1}{x ^{4}}

= \frac{49 y ^{2}}{x ^{6}} \cdot 2 \cdot \frac{1}{x ^{4}} y^{- 2}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

y^{- 2} = \frac{1}{y ^{2}}

= \frac{49 y ^{2}}{x ^{6}} \cdot 2 \cdot \frac{1}{x ^{4}} \cdot \frac{1}{y ^{2}}

Apply the fraction rule:

a \cdot \frac{b}{c} \cdot \frac{d}{e} = \frac{a \cdot b \cdot d}{c \cdot e}

= \frac{49 y ^{2} \cdot 2 \cdot 1 \cdot 1}{x ^{6} x ^{4} y ^{2}}

Multiply the numbers:

49 \cdot 2 \cdot 1 \cdot 1 = 98

= \frac{98 y ^{2}}{x ^{6} x ^{4} y ^{2}}

Cancel the common factor:

y^{2}

= \frac{98}{x ^{6} x ^{4}}

Simplify

x^{6} x^{4} : x^{10}

= \frac{98}{x ^{10}}

1.0 8^{10}

\frac{2}{x + 1} + \frac{2}{x - 1} + \frac{1}{x ^{2} - 1}

\frac{16}{3} + \frac{16}{3}

\frac{x + 4}{6} + \frac{x + 3}{15}

(x + 7) (3 x - 2)

What is (-7x^{-3}y)^2*2x^{-4}y^{-2} ?
The solution to (-7x^{-3}y)^2*2x^{-4}y^{-2} is (98)/(x^{10)}