What is (x^2-4x)/(x^2+x-20) ?

The solution to (x^2-4x)/(x^2+x-20) is x/(x+5)

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simplify (x^2-4x)/(x^2+x-20)

simplify

\frac{x ^{2} - 4 x}{x ^{2} + x - 20}

\frac{x}{x + 5}

Solution steps

\frac{x ^{2} - 4 x}{x ^{2} + x - 20}

Factor

x^{2} - 4 x : x (x - 4)

= \frac{x ( x - 4 )}{x ^{2} + x - 20}

Factor

x^{2} + x - 20 : (x - 4) (x + 5)

= \frac{x ( x - 4 )}{( x - 4 ) ( x + 5 )}

Cancel the common factor:

x - 4

= \frac{x}{x + 5}

(x^{2} - 2 x)^{3}

32 - 8

- 8 x + 9 x - x

\frac{54}{12}