What is (2t+1/(t^2))^{10} ?

The solution to (2t+1/(t^2))^{10} is ((2t^3+1)^{10})/(t^{20)}

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simplify (2t+1/(t^2))^{10}

simplify

(2 t + \frac{1}{t ^{2}})^{10}

\frac{( 2 t ^{3} + 1 ) ^{10}}{t ^{20}}

Solution steps

(2 t + \frac{1}{t ^{2}})^{10}

Join

2 t + \frac{1}{t ^{2}} : \frac{2 t ^{3} + 1}{t ^{2}}

= (\frac{2 t ^{3} + 1}{t ^{2}})^{10}

Apply exponent rule:

(\frac{a}{b})^{c} = \frac{a ^{c}}{b ^{c}}

= \frac{( 2 t ^{3} + 1 ) ^{10}}{( t ^{2} ) ^{10}}

Simplify

(t^{2})^{10} : t^{20}

= \frac{( 2 t ^{3} + 1 ) ^{10}}{t ^{20}}

\frac{15}{2 5}

(- 2 r^{2} s)^{5} (3 r^{- 1} s^{3})^{2}

\frac{4 ^{\frac{5}{4}}}{4}

18 \cdot (\frac{2}{3})

(3 x + 7) (3 x + 4)

What is (2t+1/(t^2))^{10} ?
The solution to (2t+1/(t^2))^{10} is ((2t^3+1)^{10})/(t^{20)}