What is factor 4x^5-29x^3-24x^2+7x+6 ?

The solution to factor 4x^5-29x^3-24x^2+7x+6 is (x+1)(2x-1)(2x+1)(x+2)(x-3)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

factor 4x^5-29x^3-24x^2+7x+6

factor

4 x^{5} - 29 x^{3} - 24 x^{2} + 7 x + 6

(x + 1) (2 x - 1) (2 x + 1) (x + 2) (x - 3)

Solution steps

4 x^{5} - 29 x^{3} - 24 x^{2} + 7 x + 6

Use the rational root theorem

= (x + 1) \frac{4 x ^{5} - 29 x ^{3} - 24 x ^{2} + 7 x + 6}{x + 1}

\frac{4 x ^{5} - 29 x ^{3} - 24 x ^{2} + 7 x + 6}{x + 1} = 4 x^{4} - 4 x^{3} - 25 x^{2} + x + 6

= (x + 1) (4 x^{4} - 4 x^{3} - 25 x^{2} + x + 6)

Factor

4 x^{4} - 4 x^{3} - 25 x^{2} + x + 6 : (2 x - 1) (2 x + 1) (x + 2) (x - 3)

= (x + 1) (2 x - 1) (2 x + 1) (x + 2) (x - 3)

\frac{- 3 ^{0}}{( - 3 ) ^{2}}

\frac{1}{cot ^{2} ( x )}

y^{2} + 8 y

(9)^{2} + (- 27)^{2}

\frac{sin ( x )}{cot ( x )}

What is factor 4x^5-29x^3-24x^2+7x+6 ?
The solution to factor 4x^5-29x^3-24x^2+7x+6 is (x+1)(2x-1)(2x+1)(x+2)(x-3)