What are the solutions to the equation c^2-6c=0 ?

The solutions to the equation c^2-6c=0 are c=6,c=0

Find the zeros of c^2-6c=0

The zeros of c^2-6c=0 are c=6,c=0

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c^{2} - 6 c = 0

c = 6, c = 0

Solution steps

c^{2} - 6 c = 0

Solve with the quadratic formula

c_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

(- 6)^{2} - 4 \cdot 1 \cdot 0 = 6

c_{1, 2} = \frac{- ( - 6 ) \pm 6}{2 \cdot 1}

Separate the solutions

c_{1} = \frac{- ( - 6 ) + 6}{2 \cdot 1}, c_{2} = \frac{- ( - 6 ) - 6}{2 \cdot 1}

c = \frac{- ( - 6 ) + 6}{2 \cdot 1} : 6

c = \frac{- ( - 6 ) - 6}{2 \cdot 1} : 0

The solutions to the quadratic equation are:

c = 6, c = 0

16 x y^{3} - 84 x^{2} y^{2} + 108 x^{3} y

- 4 \leq 3 x - 1

- 4 (x + 2) < - \frac{1}{2} (4 x - 4)

1.5 x = 0.33

x^{3} + x^{2} y - x y^{2} - y^{3}

What are the solutions to the equation c^2-6c=0 ?
The solutions to the equation c^2-6c=0 are c=6,c=0
Find the zeros of c^2-6c=0
The zeros of c^2-6c=0 are c=6,c=0