What is (4x^3-4+7x)-(2x^3-x-8) ?

The solution to (4x^3-4+7x)-(2x^3-x-8) is 2x^3+8x+4

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simplify (4x^3-4+7x)-(2x^3-x-8)

simplify

(4 x^{3} - 4 + 7 x) - (2 x^{3} - x - 8)

2 x^{3} + 8 x + 4

Solution steps

(4 x^{3} - 4 + 7 x) - (2 x^{3} - x - 8)

Apply rule:

(a) = a

(4 x^{3} - 4 + 7 x) = 4 x^{3} - 4 + 7 x

= 4 x^{3} - 4 + 7 x - (2 x^{3} - x - 8)

Apply the distributive law:

- (a - b) = - a + b

- (2 x^{3} - x - 8) = - 2 x^{3} + x + 8

= 4 x^{3} - 4 + 7 x - 2 x^{3} + x + 8

Group like terms

= 4 x^{3} - 2 x^{3} + 7 x + x - 4 + 8

Add similar elements:

4 x^{3} - 2 x^{3} = 2 x^{3}

= 2 x^{3} + 7 x + x - 4 + 8

Add similar elements:

7 x + x = 8 x

= 2 x^{3} + 8 x - 4 + 8

Add the numbers:

- 4 + 8 = 4

= 2 x^{3} + 8 x + 4

\frac{2}{5} + \frac{3}{5} + \frac{4}{5}

\frac{\frac{16}{9} + ( 0.6 ) ^{- 2} + ( - \frac{1}{2} ) ^{3}}{1.5}

15 \cdot 15 \cdot 15

(6 r + 7) + (13 + 7 r)

\frac{17}{20}

What is (4x^3-4+7x)-(2x^3-x-8) ?
The solution to (4x^3-4+7x)-(2x^3-x-8) is 2x^3+8x+4