What is (\frac{x^2+x-20)/(x+1)}{(11x+55)/(x+1)} ?

The solution to (\frac{x^2+x-20)/(x+1)}{(11x+55)/(x+1)} is (x-4)/(11)

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simplify (\frac{x^2+x-20)/(x+1)}{(11x+55)/(x+1)}

simplify

\frac{\frac{x ^{2} + x - 20}{x + 1}}{\frac{11 x + 55}{x + 1}}

\frac{x - 4}{11}

Solution steps

\frac{\frac{x ^{2} + x - 20}{x + 1}}{\frac{11 x + 55}{x + 1}}

Apply the fraction rule:

\frac{\frac{a}{b}}{\frac{c}{d}} = \frac{a \cdot d}{b \cdot c}

= \frac{( x ^{2} + x - 20 ) ( x + 1 )}{( x + 1 ) ( 11 x + 55 )}

Cancel the common factor:

x + 1

= \frac{x ^{2} + x - 20}{11 x + 55}

Factor

x^{2} + x - 20 : (x - 4) (x + 5)

= \frac{( x - 4 ) ( x + 5 )}{11 x + 55}

Factor

11 x + 55 : 11 (x + 5)

= \frac{( x - 4 ) ( x + 5 )}{11 ( x + 5 )}

Cancel the common factor:

x + 5

= \frac{x - 4}{11}

\frac{a - a + 1}{a + a + 1}

- 2 x^{2} + 2 x + 4

5^{- \frac{1}{5}}

(2 7^{p - 1} 0. 9^{3 - p})^{2}

\frac{40 - 36}{\frac{10.5}{20}}

What is (\frac{x^2+x-20)/(x+1)}{(11x+55)/(x+1)} ?
The solution to (\frac{x^2+x-20)/(x+1)}{(11x+55)/(x+1)} is (x-4)/(11)