What is log_{2}(x+2)+log_{2}(x-2) ?

The solution to log_{2}(x+2)+log_{2}(x-2) is log_{2}((x+2)(x-2))

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simplify log_{2}(x+2)+log_{2}(x-2)

simplify

lo g_{2} (x + 2) + lo g_{2} (x - 2)

lo g_{2} ((x + 2) (x - 2))

Solution steps

lo g_{2} (x + 2) + lo g_{2} (x - 2)

Apply log rule:

lo g_{a} (x) + lo g_{a} (y) = lo g_{a} (x y)

lo g_{2} (x + 2) + lo g_{2} (x - 2) = lo g_{2} ((x + 2) (x - 2))

= lo g_{2} ((x + 2) (x - 2))

\frac{\frac{π}{2}}{2 π}

1 + (2 x - \frac{1}{8 x})^{2}

- \frac{1}{8} + \frac{1}{4}

(a + x)^{2}

\frac{f ( - 13 ) - ( - 13 - 12 h - 2 h ^{2} )}{h}

What is log_{2}(x+2)+log_{2}(x-2) ?
The solution to log_{2}(x+2)+log_{2}(x-2) is log_{2}((x+2)(x-2))