What is (e^{3x}+1)/(e^x+1) ?

The solution to (e^{3x}+1)/(e^x+1) is e^{2x}-e^x+1

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simplify (e^{3x}+1)/(e^x+1)

simplify

\frac{e ^{3 x} + 1}{e ^{x} + 1}

e^{2 x} - e^{x} + 1

Solution steps

\frac{e ^{3 x} + 1}{e ^{x} + 1}

Factor

e^{3 x} + 1 : (e^{x} + 1) (e^{2 x} - e^{x} + 1)

= \frac{( e ^{x} + 1 ) ( e ^{2 x} - e ^{x} + 1 )}{e ^{x} + 1}

Cancel the common factor:

e^{x} + 1

= e^{2 x} - e^{x} + 1

x^{3} - x^{4}

31 + 21 + 13 + 9

\frac{12 k ^{2} h - 3 k h ^{2}}{3 kh}

- (- 2^{2})

(2 n^{3})^{2}