What is 1/((\frac{0.000002){800})^2+1/300000000} ?

The solution to 1/((\frac{0.000002){800})^2+1/300000000} is 1/(\frac{1){1.6E17}+1/300000000}

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simplify 1/((\frac{0.000002){800})^2+1/300000000}

simplify

\frac{1}{( \frac{0.000002}{800} ) ^{2} + \frac{1}{300000000}}

\frac{1}{\frac{1}{1.6 E 17} + \frac{1}{300000000}}

Solution steps

\frac{1}{( \frac{0.000002}{800} ) ^{2} + \frac{1}{300000000}}

Apply exponent rule:

(\frac{a}{b})^{c} = \frac{a ^{c}}{b ^{c}}

(\frac{0.000002}{800})^{2} = \frac{0.00000 2 ^{2}}{80 0 ^{2}}

= \frac{1}{\frac{0.00000 2 ^{2}}{80 0 ^{2}} + \frac{1}{300000000}}

0.00000 2^{2} = 4.0 E - 12

= \frac{1}{\frac{4.0 E - 12}{80 0 ^{2}} + \frac{1}{300000000}}

80 0^{2} = 640000

= \frac{1}{\frac{4.0 E - 12}{640000} + \frac{1}{300000000}}

\frac{4.0 E - 12}{640000} = \frac{4}{6.4 E 17}

= \frac{1}{\frac{4}{6.4 E 17} + \frac{1}{300000000}}

Factor the number:

6.4 E 17 = 4 \cdot 1.6 E 17

= \frac{1}{\frac{4}{4 \cdot 1.6 E 17} + \frac{1}{300000000}}

Divide the numbers:

\frac{4}{4} = 1

= \frac{1}{\frac{1}{1.6 E 17} + \frac{1}{300000000}}

\frac{2}{3} + \frac{1}{2} \cdot 3

lo g_{3} (4) - lo g_{3} (2)

\frac{13 !}{11 !}

- \frac{7}{9} \div \frac{9}{8}

What is 1/((\frac{0.000002){800})^2+1/300000000} ?
The solution to 1/((\frac{0.000002){800})^2+1/300000000} is 1/(\frac{1){1.6E17}+1/300000000}