What is (3y^2-4y+1)+(-y^2+y-2) ?

The solution to (3y^2-4y+1)+(-y^2+y-2) is 2y^2-3y-1

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simplify (3y^2-4y+1)+(-y^2+y-2)

simplify

(3 y^{2} - 4 y + 1) + (- y^{2} + y - 2)

2 y^{2} - 3 y - 1

Solution steps

(3 y^{2} - 4 y + 1) + (- y^{2} + y - 2)

Simplify

(3 y^{2} - 4 y + 1) + (- y^{2} + y - 2) : 3 y^{2} - 4 y + 1 - y^{2} + y - 2

= 3 y^{2} - 4 y + 1 - y^{2} + y - 2

Group like terms

= 3 y^{2} - y^{2} - 4 y + y + 1 - 2

Add similar elements:

3 y^{2} - y^{2} = 2 y^{2}

= 2 y^{2} - 4 y + y + 1 - 2

Add similar elements:

- 4 y + y = - 3 y

= 2 y^{2} - 3 y + 1 - 2

Subtract the numbers:

1 - 2 = - 1

= 2 y^{2} - 3 y - 1

ln (\frac{3 e}{2})

\frac{\frac{16}{x - 2}}{\frac{4}{x + 1} + \frac{6}{x}}

\frac{15 x ^{2} + 30 x}{5 x ^{2}}

\frac{1}{0 + 1}

What is (3y^2-4y+1)+(-y^2+y-2) ?
The solution to (3y^2-4y+1)+(-y^2+y-2) is 2y^2-3y-1