What is expand (2x^2+5x+5)(4x-3) ?

The solution to expand (2x^2+5x+5)(4x-3) is 8x^3+14x^2+5x-15

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand (2x^2+5x+5)(4x-3)

expand

(2 x^{2} + 5 x + 5) (4 x - 3)

8 x^{3} + 14 x^{2} + 5 x - 15

Solution steps

(2 x^{2} + 5 x + 5) (4 x - 3)

Distribute parentheses

= 2 x^{2} \cdot 4 x + 2 x^{2} (- 3) + 5 x \cdot 4 x + 5 x (- 3) + 5 \cdot 4 x + 5 (- 3)

Simplify

2 x^{2} \cdot 4 x + 2 x^{2} (- 3) + 5 x \cdot 4 x + 5 x (- 3) + 5 \cdot 4 x + 5 (- 3) : 8 x^{3} + 14 x^{2} + 5 x - 15

= 8 x^{3} + 14 x^{2} + 5 x - 15

\frac{( 1 - 3 i ) ^{5}}{( 1 + i ) ^{4}}

\frac{2 7 - 3}{7 + 2}

\frac{120}{7}

5.3 x - 8.14 + 3.6 x + 9.8

(3 m - 4)^{3} (3 m^{5})

What is expand (2x^2+5x+5)(4x-3) ?
The solution to expand (2x^2+5x+5)(4x-3) is 8x^3+14x^2+5x-15