What is expand (2x^2-3x)(3x^2+2x-1) ?

The solution to expand (2x^2-3x)(3x^2+2x-1) is 6x^4-5x^3-8x^2+3x

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expand (2x^2-3x)(3x^2+2x-1)

expand

(2 x^{2} - 3 x) (3 x^{2} + 2 x - 1)

6 x^{4} - 5 x^{3} - 8 x^{2} + 3 x

Solution steps

(2 x^{2} - 3 x) (3 x^{2} + 2 x - 1)

Distribute parentheses

= 2 x^{2} \cdot 3 x^{2} + 2 x^{2} \cdot 2 x + 2 x^{2} (- 1) - 3 x \cdot 3 x^{2} - 3 x \cdot 2 x - 3 x (- 1)

Simplify

2 x^{2} \cdot 3 x^{2} + 2 x^{2} \cdot 2 x + 2 x^{2} (- 1) - 3 x \cdot 3 x^{2} - 3 x \cdot 2 x - 3 x (- 1) : 6 x^{4} - 5 x^{3} - 8 x^{2} + 3 x

= 6 x^{4} - 5 x^{3} - 8 x^{2} + 3 x

\frac{1}{5} - \frac{1}{15}

\frac{x + 3}{3} - \frac{x - 2}{7}

\frac{x ^{3} - 3 x + 2}{x - 1}

u (3 t - 1)

1.7 a^{2} + 1.7 b^{2}

What is expand (2x^2-3x)(3x^2+2x-1) ?
The solution to expand (2x^2-3x)(3x^2+2x-1) is 6x^4-5x^3-8x^2+3x