What is sqrt((3^{-1)+3^{-2})^{-1}} ?

The solution to sqrt((3^{-1)+3^{-2})^{-1}} is 3/2

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simplify sqrt((3^{-1)+3^{-2})^{-1}}

simplify

(3^{- 1} + 3^{- 2})^{- 1}

\frac{3}{2}

Decimal Notation

1.5

Solution steps

(3^{- 1} + 3^{- 2})^{- 1}

(3^{- 1} + 3^{- 2})^{- 1} = \frac{9}{4}

= \frac{9}{4}

Apply radical rule:

\frac{a}{b} = \frac{a}{b}, a \geq 0, b \geq 0

= \frac{9}{4}

9 = 3

= \frac{3}{4}

4 = 2

= \frac{3}{2}

(5 x y + 14 x + 6 y) - (8 x - 4 y + 2 x y)

3 + \frac{1}{3} - \frac{1}{12} - (1 - (2 \frac{1}{4} + 1.7))

\frac{3 x ^{2} y z ^{4}}{6 x y z ^{2}} \cdot \frac{2 x ^{2} y ^{4}}{6 x y ^{3}}

- 0.5 \cdot (- 0.5)

8 a^{2} b + 2 ab - 3 a^{2} b + ba

What is sqrt((3^{-1)+3^{-2})^{-1}} ?
The solution to sqrt((3^{-1)+3^{-2})^{-1}} is 3/2