What is expand (x^2-3x+1)(x-3) ?

The solution to expand (x^2-3x+1)(x-3) is x^3-6x^2+10x-3

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expand (x^2-3x+1)(x-3)

expand

(x^{2} - 3 x + 1) (x - 3)

x^{3} - 6 x^{2} + 10 x - 3

Solution steps

(x^{2} - 3 x + 1) (x - 3)

Distribute parentheses

= x^{2} x + x^{2} (- 3) - 3 xx - 3 x (- 3) + 1 \cdot x + 1 \cdot (- 3)

Simplify

x^{2} x + x^{2} (- 3) - 3 xx - 3 x (- 3) + 1 \cdot x + 1 \cdot (- 3) : x^{3} - 6 x^{2} + 10 x - 3

= x^{3} - 6 x^{2} + 10 x - 3

\frac{5}{2} + \frac{15}{4} + \frac{25}{6} + \frac{14}{3}

7 (\frac{2110}{124 - 23})^{2} - 6 (1 - 19 - 33)

4 ln (2) + ln (4)

(3 a - 4)^{2}

\frac{x}{x ^{2} - 16} - \frac{5}{x ^{2} + 5 x + 4}

What is expand (x^2-3x+1)(x-3) ?
The solution to expand (x^2-3x+1)(x-3) is x^3-6x^2+10x-3