What is (a^2b)/5-(2ab^2)/3+(3ab^2)/2-(6a^2b)/5 ?

The solution to (a^2b)/5-(2ab^2)/3+(3ab^2)/2-(6a^2b)/5 is -a^2b-(2ab^2)/3+(3ab^2)/2

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simplify (a^2b)/5-(2ab^2)/3+(3ab^2)/2-(6a^2b)/5

simplify

\frac{a ^{2} b}{5} - \frac{2 a b ^{2}}{3} + \frac{3 a b ^{2}}{2} - \frac{6 a ^{2} b}{5}

- a^{2} b - \frac{2 a b ^{2}}{3} + \frac{3 a b ^{2}}{2}

Solution steps

\frac{a ^{2} b}{5} - \frac{2 a b ^{2}}{3} + \frac{3 a b ^{2}}{2} - \frac{6 a ^{2} b}{5}

Join

\frac{a ^{2} b}{5} - \frac{2 a b ^{2}}{3} + \frac{3 a b ^{2}}{2} - \frac{6 a ^{2} b}{5} : \frac{- 5 a ^{2} b}{5} - \frac{2 a b ^{2}}{3} + \frac{3 a b ^{2}}{2}

= \frac{- 5 a ^{2} b}{5} - \frac{2 a b ^{2}}{3} + \frac{3 a b ^{2}}{2}

Apply the fraction rule:

\frac{- a}{b} = - \frac{a}{b}

\frac{- 5 a ^{2} b}{5} = - \frac{5 a ^{2} b}{5}

= - \frac{5 a ^{2} b}{5} - \frac{2 a b ^{2}}{3} + \frac{3 a b ^{2}}{2}

Cancel the common factor:

5

= - a^{2} b - \frac{2 a b ^{2}}{3} + \frac{3 a b ^{2}}{2}

22 m^{7} \cdot 8 m^{2}

6 (x + 4)

(a + b) (a + c) (b + c)

\frac{4}{3 8}

cos (x) - cos (x) sin^{2} (x)

What is (a^2b)/5-(2ab^2)/3+(3ab^2)/2-(6a^2b)/5 ?
The solution to (a^2b)/5-(2ab^2)/3+(3ab^2)/2-(6a^2b)/5 is -a^2b-(2ab^2)/3+(3ab^2)/2