What is (x^2+6x-7)/(x^2-x) ?

The solution to (x^2+6x-7)/(x^2-x) is (x+7)/x

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simplify (x^2+6x-7)/(x^2-x)

simplify

\frac{x ^{2} + 6 x - 7}{x ^{2} - x}

\frac{x + 7}{x}

Solution steps

\frac{x ^{2} + 6 x - 7}{x ^{2} - x}

Factor

x^{2} + 6 x - 7 : (x - 1) (x + 7)

= \frac{( x - 1 ) ( x + 7 )}{x ^{2} - x}

Factor

x^{2} - x : x (x - 1)

= \frac{( x - 1 ) ( x + 7 )}{x ( x - 1 )}

Cancel the common factor:

x - 1

= \frac{x + 7}{x}

\frac{x ^{2} + y ^{2}}{x ^{2} + y ^{2} + 1 - 1}

\frac{m ^{2} - 2 m + 1}{m - 1}

\frac{11}{30}

\frac{3 x ^{3} - 4 x ^{2} - 5 x + 2}{x - 2}

x \cdot (x + 1)