What is 2+{(9-3)/3 (8/(6/3)-10)} ?

The solution to 2+{(9-3)/3 (8/(6/3)-10)} is -10

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simplify 2+{(9-3)/3 (8/(6/3)-10)}

simplify

2 + {\frac{9 - 3}{3} (\frac{8}{\frac{6}{3}} - 10)}

- 10

Solution steps

2 + (\frac{9 - 3}{3} (\frac{8}{\frac{6}{3}} - 10))

Apply rule:

(a) = a

(\frac{9 - 3}{3} (\frac{8}{\frac{6}{3}} - 10)) = \frac{9 - 3}{3} (\frac{8}{\frac{6}{3}} - 10)

= 2 + \frac{9 - 3}{3} (\frac{8}{\frac{6}{3}} - 10)

\frac{9 - 3}{3} (\frac{8}{\frac{6}{3}} - 10) = - 12

= 2 - 12

Subtract the numbers:

2 - 12 = - 10

= - 10

4 sin^{2} (t) + 4 cos^{2} (t)

\frac{14 - 7 x}{7}

e^{3 l n (t)}

x^{2} (x^{2} + 2)

(q - 1)^{2}

What is 2+{(9-3)/3 (8/(6/3)-10)} ?
The solution to 2+{(9-3)/3 (8/(6/3)-10)} is -10