What is factor 4m^2-20my+25y^2 ?

The solution to factor 4m^2-20my+25y^2 is (2m-5y)^2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

factor 4m^2-20my+25y^2

factor

4 m^{2} - 20 m y + 25 y^{2}

(2 m - 5 y)^{2}

Solution steps

4 m^{2} - 20 m y + 25 y^{2}

Rewrite in the form of

a^{2} + 2 ab + b^{2} :

4 m^{2} = (2 m)^{2}

25 y^{2} = (5 y)^{2}

- 20 m y = - 2 \cdot 2 m \cdot 5 y

= (2 m)^{2} - 2 \cdot 2 m \cdot 5 y + (5 y)^{2}

Apply Perfect Square Formula:

a^{2} - 2 ab + b^{2} = (a - b)^{2}

(2 m)^{2} - 2 \cdot 2 m \cdot 5 y + (5 y)^{2} = (2 m - 5 y)^{2}

= (2 m - 5 y)^{2}

\frac{( - 5 ) ^{3} \cdot 4 ^{6} \cdot ( - 5 ) ^{2}}{4 \cdot ( - 5 ) ^{4}}

\frac{- 7}{- 5}

(sin (x))^{2} + (cos (x))^{2}

7 \cdot 17

\frac{24}{10}

What is factor 4m^2-20my+25y^2 ?
The solution to factor 4m^2-20my+25y^2 is (2m-5y)^2