What is (7/(10(n+3)))/(\frac{n-2){(n+3)(n-2)}} ?

The solution to (7/(10(n+3)))/(\frac{n-2){(n+3)(n-2)}} is 7/10

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simplify (7/(10(n+3)))/(\frac{n-2){(n+3)(n-2)}}

simplify

\frac{\frac{7}{10 ( n + 3 )}}{\frac{n - 2}{( n + 3 ) ( n - 2 )}}

\frac{7}{10}

Decimal Notation

0.7

Solution steps

\frac{\frac{7}{10 ( n + 3 )}}{\frac{n - 2}{( n + 3 ) ( n - 2 )}}

Apply the fraction rule:

\frac{\frac{a}{b}}{\frac{c}{d}} = \frac{a \cdot d}{b \cdot c}

= \frac{7 ( n + 3 ) ( n - 2 )}{10 ( n + 3 ) ( n - 2 )}

Cancel the common factor:

n + 3

= \frac{7 ( n - 2 )}{10 ( n - 2 )}

Cancel the common factor:

n - 2

= \frac{7}{10}

(5 - 3 x) + (2 x - 8)

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(a^{2} + 2 b)^{3}

What is (7/(10(n+3)))/(\frac{n-2){(n+3)(n-2)}} ?
The solution to (7/(10(n+3)))/(\frac{n-2){(n+3)(n-2)}} is 7/10