What is (4x)/(x^2-4)*(x+2)/(16x) ?

The solution to (4x)/(x^2-4)*(x+2)/(16x) is 1/(4(x-2))

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simplify (4x)/(x^2-4)*(x+2)/(16x)

simplify

\frac{4 x}{x ^{2} - 4} \cdot \frac{x + 2}{16 x}

\frac{1}{4 ( x - 2 )}

Solution steps

\frac{4 x}{x ^{2} - 4} \cdot \frac{x + 2}{16 x}

Apply the fraction rule:

\frac{a}{b} \cdot \frac{c}{d} = \frac{a \cdot c}{b \cdot d}

= \frac{4 x ( x + 2 )}{( x ^{2} - 4 ) \cdot 16 x}

Cancel the common factor:

x

= \frac{4 ( x + 2 )}{( x ^{2} - 4 ) \cdot 16}

Factor the number:

16 = 4 \cdot 4

= \frac{4 ( x + 2 )}{( x ^{2} - 4 ) \cdot 4 \cdot 4}

Cancel the common factor:

4

= \frac{x + 2}{( x ^{2} - 4 ) \cdot 4}

Factor

x^{2} - 4 : (x + 2) (x - 2)

= \frac{x + 2}{( x + 2 ) ( x - 2 ) \cdot 4}

Cancel the common factor:

x + 2

= \frac{1}{( x - 2 ) \cdot 4}

= \frac{1}{4 ( x - 2 )}

cot^{2} (x) (1 + tan^{2} (x))

(5 x - 2) (2 y - 5)

\frac{2 a + 2}{a ^{2} - 1}

\frac{1 + i}{3 + i}

\frac{1}{12} \cdot 2

What is (4x)/(x^2-4)*(x+2)/(16x) ?
The solution to (4x)/(x^2-4)*(x+2)/(16x) is 1/(4(x-2))