What is expand 3(x-1)(x+2) ?

The solution to expand 3(x-1)(x+2) is 3x^2+3x-6

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expand 3(x-1)(x+2)

expand

3 (x - 1) (x + 2)

3 x^{2} + 3 x - 6

Solution steps

3 (x - 1) (x + 2)

Expand

3 (x - 1) (x + 2) : 3 (x^{2} + x - 2)

= 3 (x^{2} + x - 2)

Apply the distributive law:

m (a + b + c) = ma + mb + m c

3 (x^{2} + x - 2) = 3 x^{2} + 3 x + 3 (- 2)

= 3 x^{2} + 3 x + 3 (- 2)

Multiply the numbers:

3 (- 2) = - 6

= 3 x^{2} + 3 x - 6

\frac{1}{8} \cdot \frac{4}{5}

24 \cdot 3 \cdot 6

73 + 73

(1 + \frac{x}{2})^{5}

(1 + \frac{x}{2})^{6}