What is (x+8)/(x^2+13x+40)*(x^2-25)/(9x^2) ?

The solution to (x+8)/(x^2+13x+40)*(x^2-25)/(9x^2) is (x-5)/(9x^2)

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simplify (x+8)/(x^2+13x+40)*(x^2-25)/(9x^2)

simplify

\frac{x + 8}{x ^{2} + 13 x + 40} \cdot \frac{x ^{2} - 25}{9 x ^{2}}

\frac{x - 5}{9 x ^{2}}

Solution steps

\frac{x + 8}{x ^{2} + 13 x + 40} \cdot \frac{x ^{2} - 25}{9 x ^{2}}

Cancel

\frac{x + 8}{x ^{2} + 13 x + 40} : \frac{1}{x + 5}

= \frac{1}{x + 5} \cdot \frac{x ^{2} - 25}{9 x ^{2}}

Apply the fraction rule:

\frac{a}{b} \cdot \frac{c}{d} = \frac{a \cdot c}{b \cdot d}

= \frac{1 \cdot ( x ^{2} - 25 )}{( x + 5 ) \cdot 9 x ^{2}}

Apply rule:

1 \cdot a = a

1 \cdot (x^{2} - 25) = (x^{2} - 25)

= \frac{x ^{2} - 25}{( x + 5 ) \cdot 9 x ^{2}}

Factor

x^{2} - 25 : (x + 5) (x - 5)

= \frac{( x + 5 ) ( x - 5 )}{( x + 5 ) \cdot 9 x ^{2}}

Cancel the common factor:

x + 5

= \frac{x - 5}{9 x ^{2}}

lo g_{7} (98)

\frac{( 3 )}{( b - 3 )} + \frac{( b )}{( b - 3 )}

6.24 x 1 0^{18} \cdot 240

\frac{a ^{2}}{a ^{5}}

9 2^{2}

What is (x+8)/(x^2+13x+40)*(x^2-25)/(9x^2) ?
The solution to (x+8)/(x^2+13x+40)*(x^2-25)/(9x^2) is (x-5)/(9x^2)