What is (x^2-1)/(x+1)*(x+3)/(3x-3) ?

The solution to (x^2-1)/(x+1)*(x+3)/(3x-3) is (x+3)/3

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simplify (x^2-1)/(x+1)*(x+3)/(3x-3)

simplify

\frac{x ^{2} - 1}{x + 1} \cdot \frac{x + 3}{3 x - 3}

\frac{x + 3}{3}

Solution steps

\frac{x ^{2} - 1}{x + 1} \cdot \frac{x + 3}{3 x - 3}

Cancel

\frac{x ^{2} - 1}{x + 1} : x - 1

= (x - 1) \frac{x + 3}{3 x - 3}

Apply the fraction rule:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{( x - 1 ) ( x + 3 )}{3 x - 3}

Factor

3 x - 3 : 3 (x - 1)

= \frac{( x - 1 ) ( x + 3 )}{3 ( x - 1 )}

Cancel the common factor:

x - 1

= \frac{x + 3}{3}

(x^{2} - 3)^{7}

\frac{( 2 b ) ^{3}}{6 b ^{5}}

(x + 2) (x + 3) - (x + 4) (x + 1)

(- 2) - (- 2)

What is (x^2-1)/(x+1)*(x+3)/(3x-3) ?
The solution to (x^2-1)/(x+1)*(x+3)/(3x-3) is (x+3)/3