What is ((2x^{-1}y^{-2})^{-3})/((5x^{-1)y^3)^2} ?

The solution to ((2x^{-1}y^{-2})^{-3})/((5x^{-1)y^3)^2} is (x^5)/(200)

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simplify ((2x^{-1}y^{-2})^{-3})/((5x^{-1)y^3)^2}

simplify

\frac{( 2 x ^{- 1} y ^{- 2} ) ^{- 3}}{( 5 x ^{- 1} y ^{3} ) ^{2}}

\frac{x ^{5}}{200}

Solution steps

\frac{( 2 x ^{- 1} y ^{- 2} ) ^{- 3}}{( 5 x ^{- 1} y ^{3} ) ^{2}}

Simplify

(2 x^{- 1} y^{- 2})^{- 3} : \frac{x ^{3} y ^{6}}{8}

= \frac{\frac{x ^{3} y ^{6}}{8}}{( 5 x ^{- 1} y ^{3} ) ^{2}}

Apply the fraction rule:

\frac{\frac{a}{b}}{c} = \frac{a}{b \cdot c}

= \frac{x ^{3} y ^{6}}{8 ( 5 x ^{- 1} y ^{3} ) ^{2}}

Simplify

8 (5 x^{- 1} y^{3})^{2} : \frac{200 y ^{6}}{x ^{2}}

= \frac{x ^{3} y ^{6}}{\frac{200 y ^{6}}{x ^{2}}}

Apply the fraction rule:

\frac{a}{\frac{b}{c}} = \frac{a \cdot c}{b}

= \frac{x ^{3} y ^{6} x ^{2}}{200 y ^{6}}

Cancel

\frac{x ^{3} y ^{6} x ^{2}}{200 y ^{6}} : \frac{x ^{5}}{200}

= \frac{x ^{5}}{200}

\frac{( 3 + 2 i )}{( 3 - 2 i )}

\frac{7}{100}

\frac{2 ^{21}}{2 ^{24}}

\frac{x ^{3} + x - 2 x ^{2} y - 2 y}{x ^{2} y + x ^{2} + y + 1}

e^{x l n (a)}

What is ((2x^{-1}y^{-2})^{-3})/((5x^{-1)y^3)^2} ?
The solution to ((2x^{-1}y^{-2})^{-3})/((5x^{-1)y^3)^2} is (x^5)/(200)