What is ((-15x^2-8y^2+22xy))/((2y-3x)) ?

The solution to ((-15x^2-8y^2+22xy))/((2y-3x)) is 5x-4y

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simplify ((-15x^2-8y^2+22xy))/((2y-3x))

simplify

\frac{( - 15 x ^{2} - 8 y ^{2} + 22 x y )}{( 2 y - 3 x )}

5 x - 4 y

Solution steps

\frac{- 15 x ^{2} - 8 y ^{2} + 22 x y}{2 y - 3 x}

Factor out

- 1 : - (15 x^{2} + 8 y^{2} - 22 x y)

= \frac{- ( 15 x ^{2} + 8 y ^{2} - 22 x y )}{2 y - 3 x}

Factor

15 x^{2} + 8 y^{2} - 22 x y : (3 x - 2 y) (5 x - 4 y)

= \frac{- ( 3 x - 2 y ) ( 5 x - 4 y )}{2 y - 3 x}

2 y - 3 x = - (3 x - 2 y)

= \frac{- ( 3 x - 2 y ) ( 5 x - 4 y )}{- ( 3 x - 2 y )}

Cancel the common factor:

3 x - 2 y

= \frac{- ( 5 x - 4 y )}{- 1}

Apply the fraction rule:

\frac{- a}{- b} = \frac{a}{b}

= \frac{5 x - 4 y}{1}

Apply the fraction rule:

\frac{a}{1} = a

= 5 x - 4 y

\frac{1}{2} \cdot 2

cos^{2} (x) tan^{2} (x)

(5 x - 3) - (3 x + 2)

\frac{3}{10} \cdot \frac{3}{5}

- 3 x + 5 + 3 x^{2} + x - 8

What is ((-15x^2-8y^2+22xy))/((2y-3x)) ?
The solution to ((-15x^2-8y^2+22xy))/((2y-3x)) is 5x-4y