What are the solutions to the equation x^2-x=25 ?

The solutions to the equation x^2-x=25 are x=(1+sqrt(101))/2 ,x=(1-sqrt(101))/2

Find the zeros of x^2-x=25

The zeros of x^2-x=25 are x=(1+sqrt(101))/2 ,x=(1-sqrt(101))/2

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x^{2} - x = 25

x = \frac{1 + 101}{2}, x = \frac{1 - 101}{2}

Solution steps

x^{2} - x = 25

Move

25

to the left side

x^{2} - x - 25 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 1 \cdot ( - 25 )}{2 \cdot 1}

(- 1)^{2} - 4 \cdot 1 \cdot (- 25) = 101

x_{1, 2} = \frac{- ( - 1 ) \pm 101}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 101}{2 \cdot 1}, x_{2} = \frac{- ( - 1 ) - 101}{2 \cdot 1}

x = \frac{- ( - 1 ) + 101}{2 \cdot 1} : \frac{1 + 101}{2}

x = \frac{- ( - 1 ) - 101}{2 \cdot 1} : \frac{1 - 101}{2}

The solutions to the quadratic equation are:

x = \frac{1 + 101}{2}, x = \frac{1 - 101}{2}

7 (12 - x) = 63

\frac{( 1.05 - 0.95 ) ^{2}}{12}

s^{2} + 5 s + 6

∣ - 4 x ∣ = 11

100 f - 50 = 50 f + 50

What are the solutions to the equation x^2-x=25 ?
The solutions to the equation x^2-x=25 are x=(1+sqrt(101))/2 ,x=(1-sqrt(101))/2
Find the zeros of x^2-x=25
The zeros of x^2-x=25 are x=(1+sqrt(101))/2 ,x=(1-sqrt(101))/2