What is (x^2-5x+4)/(x^3-4x^2) ?

The solution to (x^2-5x+4)/(x^3-4x^2) is (x-1)/(x^2)

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simplify (x^2-5x+4)/(x^3-4x^2)

simplify

\frac{x ^{2} - 5 x + 4}{x ^{3} - 4 x ^{2}}

\frac{x - 1}{x ^{2}}

Solution steps

\frac{x ^{2} - 5 x + 4}{x ^{3} - 4 x ^{2}}

Factor

x^{2} - 5 x + 4 : (x - 1) (x - 4)

= \frac{( x - 1 ) ( x - 4 )}{x ^{3} - 4 x ^{2}}

Factor

x^{3} - 4 x^{2} : x^{2} (x - 4)

= \frac{( x - 1 ) ( x - 4 )}{x ^{2} ( x - 4 )}

Cancel the common factor:

x - 4

= \frac{x - 1}{x ^{2}}

2 \cdot π \cdot 1

4 - \frac{2 [ 5 - 2 ( 4 - 2 ) ]}{2}

(\frac{1}{2} x + 2)^{2}

r^{2} + r^{2}

(3 x + 4) (x - 7)

What is (x^2-5x+4)/(x^3-4x^2) ?
The solution to (x^2-5x+4)/(x^3-4x^2) is (x-1)/(x^2)