What is expand (x^2-3x+2)^2 ?

The solution to expand (x^2-3x+2)^2 is x^4-6x^3+13x^2-12x+4

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expand (x^2-3x+2)^2

expand

(x^{2} - 3 x + 2)^{2}

x^{4} - 6 x^{3} + 13 x^{2} - 12 x + 4

Solution steps

(x^{2} - 3 x + 2)^{2}

Apply exponent rule:

a^{b + c} = a^{b} \cdot a^{c}

(x^{2} - 3 x + 2)^{2} = (x^{2} - 3 x + 2) (x^{2} - 3 x + 2)

= (x^{2} - 3 x + 2) (x^{2} - 3 x + 2)

Distribute parentheses

= x^{2} x^{2} + x^{2} (- 3 x) + x^{2} \cdot 2 - 3 x x^{2} - 3 x (- 3 x) - 3 x \cdot 2 + 2 x^{2} + 2 (- 3 x) + 2 \cdot 2

Simplify

x^{2} x^{2} + x^{2} (- 3 x) + x^{2} \cdot 2 - 3 x x^{2} - 3 x (- 3 x) - 3 x \cdot 2 + 2 x^{2} + 2 (- 3 x) + 2 \cdot 2 : x^{4} - 6 x^{3} + 13 x^{2} - 12 x + 4

= x^{4} - 6 x^{3} + 13 x^{2} - 12 x + 4

(\frac{3}{4} x^{2} y - \frac{1}{3} x z)^{2}

\frac{3}{4} \cdot \frac{2}{4}

2 0^{\circ} - 2 0^{g} + \frac{3}{8} π

(3 + 5 i) + (4 + i) + (12 + 5 i)

\frac{1}{x} - \frac{1}{2 x}

What is expand (x^2-3x+2)^2 ?
The solution to expand (x^2-3x+2)^2 is x^4-6x^3+13x^2-12x+4