What is (3^8)/(3^5)+(2^3*2*2^2)-(4)^3-435^0 ?

The solution to (3^8)/(3^5)+(2^3*2*2^2)-(4)^3-435^0 is 26

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simplify (3^8)/(3^5)+(2^322^2)-(4)^3-435^0

simplify

\frac{3 ^{8}}{3 ^{5}} + (2^{3} \cdot 2 \cdot 2^{2}) - (4)^{3} - 43 5^{0}

26

Solution steps

\frac{3 ^{8}}{3 ^{5}} + (2^{3} \cdot 2 \cdot 2^{2}) - 4^{3} - 43 5^{0}

Apply rule:

(a) = a

(2^{3} \cdot 2 \cdot 2^{2}) = 2^{3} \cdot 2 \cdot 2^{2}

= \frac{3 ^{8}}{3 ^{5}} + 2^{3} \cdot 2 \cdot 2^{2} - 4^{3} - 43 5^{0}

\frac{3 ^{8}}{3 ^{5}} = 27

2^{3} \cdot 2 \cdot 2^{2} = 64

4^{3} = 64

43 5^{0} = 1

= 27 + 64 - 64 - 1

Add the numbers:

27 + 64 - 64 - 1 = 26

= 26

- 6 (3 i) (- 2 i)

∣ 5 - 3 i ∣

(2 k + 1) (k - 4)

\frac{9}{2} \div \frac{1}{4}

What is (3^8)/(3^5)+(2^3*2*2^2)-(4)^3-435^0 ?
The solution to (3^8)/(3^5)+(2^3*2*2^2)-(4)^3-435^0 is 26