What is log_{10}(7)-log_{10}(3)+log_{10}(6) ?

The solution to log_{10}(7)-log_{10}(3)+log_{10}(6) is log_{10}(14)

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simplify log_{10}(7)-log_{10}(3)+log_{10}(6)

simplify

lo g_{10} (7) - lo g_{10} (3) + lo g_{10} (6)

lo g_{10} (14)

Decimal Notation

1.14612 \dots

Solution steps

lo g_{10} (7) - lo g_{10} (3) + lo g_{10} (6)

Apply log rule:

lo g_{a} (x) - lo g_{a} (y) = lo g_{a} (\frac{x}{y})

lo g_{10} (7) - lo g_{10} (3) = lo g_{10} (\frac{7}{3})

= lo g_{10} (\frac{7}{3}) + lo g_{10} (6)

Apply log rule:

lo g_{a} (x) + lo g_{a} (y) = lo g_{a} (x y)

lo g_{10} (\frac{7}{3}) + lo g_{10} (6) = lo g_{10} (\frac{7}{3} \cdot 6)

= lo g_{10} (\frac{7}{3} \cdot 6)

\frac{7}{3} \cdot 6 = 14

= lo g_{10} (14)

\frac{8}{x ^{2} + 6 x} \cdot 2 x

- \frac{2}{3} \cdot (- 1)

- 2 x (x^{2} - 3)

- 32 + 36 - 8

5 0^{2} + 78.5 3^{2}

What is log_{10}(7)-log_{10}(3)+log_{10}(6) ?
The solution to log_{10}(7)-log_{10}(3)+log_{10}(6) is log_{10}(14)