What is (b^2-10b+25)/(b^2-6b+5) ?

The solution to (b^2-10b+25)/(b^2-6b+5) is (b-5)/(b-1)

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simplify (b^2-10b+25)/(b^2-6b+5)

simplify

\frac{b ^{2} - 10 b + 25}{b ^{2} - 6 b + 5}

\frac{b - 5}{b - 1}

Solution steps

\frac{b ^{2} - 10 b + 25}{b ^{2} - 6 b + 5}

Factor

b^{2} - 10 b + 25 : (b - 5)^{2}

= \frac{( b - 5 ) ^{2}}{b ^{2} - 6 b + 5}

Factor

b^{2} - 6 b + 5 : (b - 1) (b - 5)

= \frac{( b - 5 ) ^{2}}{( b - 1 ) ( b - 5 )}

Apply exponent rule:

a^{b + c} = a^{b} \cdot a^{c}

(b - 5)^{2} = (b - 5) (b - 5)

= \frac{( b - 5 ) ( b - 5 )}{( b - 1 ) ( b - 5 )}

Cancel the common factor:

b - 5

= \frac{b - 5}{b - 1}

(2 x - y)^{4}

(y + 2)^{2}

8 + 58

(- 30)^{2}

(\frac{4}{3} \cdot 0.5)^{3}

What is (b^2-10b+25)/(b^2-6b+5) ?
The solution to (b^2-10b+25)/(b^2-6b+5) is (b-5)/(b-1)