What is 2/(x+2)>= 1/(x-1) ?

The solution to 2/(x+2)>= 1/(x-1) is -2 = 4

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2/(x+2)>= 1/(x-1)

\frac{2}{x + 2} \geq \frac{1}{x - 1}

- 2 < x < 1 or x \geq 4

Interval Notation

(- 2, 1) \cup [4, \infty)

Solution steps

\frac{2}{x + 2} \geq \frac{1}{x - 1}

Rewrite in standard form

\frac{x - 4}{( x + 2 ) ( x - 1 )} \geq 0

Identify the intervals

- 2 < x < 1 or x \geq 4

lo g_{2} (\frac{1}{32}) = - 5

(\frac{1}{1 + x ^{2}})^{2}

(x^{- 2}) (\frac{1}{2})

8 - 2 y = 3 y - 2

6 x^{2} - x y - 2 y^{2}

What is 2/(x+2)>= 1/(x-1) ?
The solution to 2/(x+2)>= 1/(x-1) is -2<x<1\lor x>= 4