What is (2a^2-a-10)-(a^2+a+13) ?

The solution to (2a^2-a-10)-(a^2+a+13) is a^2-2a-23

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simplify (2a^2-a-10)-(a^2+a+13)

simplify

(2 a^{2} - a - 10) - (a^{2} + a + 13)

a^{2} - 2 a - 23

Solution steps

(2 a^{2} - a - 10) - (a^{2} + a + 13)

Apply rule:

(a) = a

(2 a^{2} - a - 10) = 2 a^{2} - a - 10

= 2 a^{2} - a - 10 - (a^{2} + a + 13)

Apply the distributive law:

- (a + b) = - a - b

- (a^{2} + a + 13) = - a^{2} - a - 13

= 2 a^{2} - a - 10 - a^{2} - a - 13

Group like terms

= 2 a^{2} - a^{2} - a - a - 10 - 13

Add similar elements:

2 a^{2} - a^{2} = a^{2}

= a^{2} - a - a - 10 - 13

Add similar elements:

- a - a = - 2 a

= a^{2} - 2 a - 10 - 13

Subtract the numbers:

- 10 - 13 = - 23

= a^{2} - 2 a - 23

\frac{5}{6} + 2 \frac{1}{3} + 2

sec^{2} (θ) cos^{2} (θ)

(4 x^{2} - y)^{2}

- 5 \cdot (- 6)

\frac{9 - 45}{12}

What is (2a^2-a-10)-(a^2+a+13) ?
The solution to (2a^2-a-10)-(a^2+a+13) is a^2-2a-23